#include <stdio.h>
#include <stdlib.h>
#include <string.h>
struct Ecoponto{
int codigo;
int contentores[3];
char cidade[20];
char *rua;
int nporta;
};
int main(int argc, char** argv) {
struct Ecoponto ecoponto;
printf("\nIntroduza o nome da rua:");
scanf("%s",ecoponto.rua);
printf("%s",&ecoponto.rua);
return (EXIT_SUCCESS);
}
I would like to know what is the best way to save "street name" with an unknown size in the "ecoponto ecoponto" structure.
To save a string of unknown size without spending extra memory, you need to read the street name in a buffer, a very large variable that can support any street name, for example, size 1000. Then use the string library . and its strlen () function, which returns how many characters a string has and use strlen (buffer).
Now you know how many characters the street name has, if you do
char buffer[1000];
scanf("%s", buffer);
int a = strlen(buffer);
You will be able to use the malloc () function of the stdlib.h library to store how much memory you need, for example:
char *nome_rua = (char *)malloc(sizeof(char)*a);
Then you can copy the contents of the buffer to your variable, and you can use the function strcpy () of the library string.h
Source: link
You need to give malloc in (a + 1) positions, because the string must \ O, which delimits its end.
And also, you can use the
char *strncpy(char *dest, const char *src, size_t n)
Because there you would copy only the amount of characters read from the buffer.