JqGrid. onSelectRow - Get field id and pass with url

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JqGrid. onSelectRow - Get field id and pass with url

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#1 by (1 votes)

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Oops, I have the following code:

// jqGrid //
      $grid->('onSelectRow', "fnHistoricoPessoa");
// fim jqGrid//

// função para onSelectRow//

function fnHistoricoPessoa(){

var kwGrid = $("#kwGrid").jqGrid('getGridParam', 'selrow');

if(kwGrid != null)
{
    var ret = $("#kwGrid").jqGrid('getRowData',kwGrid);

    $("#grid_historico").setGridParam({url:"/admin/pessoas/listagem_historico.json?id_familia=1",page:1});
    $("#grid_historico").trigger("reloadGrid");


}

}

With this code I do in jqGrid the option of when to select a row, it fill another grid with the information I want and they are: id_familia = 1 only this 1, I botei manual only test the grid, that is it searches the database for id_familia = 1 and plays on the screen, but I do not want all screens to be id_familia = 1 , I want it to be id_familia = id da familia que o usuario está buscando .

How do I retrieve the id that the user is searching for?

php jquery postgresql jqgrid

asked by anonymous 18.03.2015 / 19:14

1 answer

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score 1 · Accepted Answer

I got it done with the help from here:

function fnHistoricoPessoa(){

var kwGrid = $("#kwGrid").jqGrid('getGridParam', 'selrow');

if(kwGrid != null)
{
    var ret = $("#kwGrid").jqGrid('getRowData',kwGrid);

    $("#grid_historico").setGridParam({url:"/admin/pessoas/listagem_historico.json?id_familia=" + ret['id_familia'], page:1});
    $("#grid_historico").trigger("reloadGrid");


}

}