from random import choice
def escolher():
a = choice([[10.00,90.00,30.00,40.00],[50.00,60.00,90.00,80.00]])
fitness_1_temp = 0
for i in a:
for j in i:
#---------------^^^
if j <= 85.0:
fitness_1_temp += j
else:
fitness_1_temp -= j
return fitness_1_temp
print (escolher())
See in the code above, the part highlighted by the comment. You are trying to iterate over a value of type float . In fact, it does not make much sense to make the two loop , only one is able to solve the sum.
Let's say choice returned the first list:
a = [10.00,90.00,30.00,40.00]
By iterating for i in a , i will have the values 10.0, 90.0, 30.0 and 40.0, depending on the current iteration. From this value, you can do the following:
fitness_1_temp = (fitness_1_temp+i) if i <= 85.0 else (fitness_1_temp-i)
For the given examples, -10.0 will be returned when the first list is considered or 100.0 when the second.
See working at Repl.it at Ideone , and in the GitHub Gist .
Workaround
When we want to reduce a list to a single value, we can use the reduce operation. In Python 2, reduce is a built-in function , whereas in Python 3 it was built into the functools module. Both have the same format:
reduce(function, iterable[, initializer])
In Python 2:
from random import choice
def escolher():
a = choice([[10.00,90.00,30.00,40.00],[50.00,60.00,90.00,80.00]])
fitness_1_temp = reduce(lambda x, y: (x+y) if y <= 85.0 else (x-y), a, 0)
return fitness_1_temp
print (escolher())
In Python 3:
from random import choice
from functools import reduce
def escolher():
a = choice([[10.00,90.00,30.00,40.00],[50.00,60.00,90.00,80.00]])
fitness_1_temp = reduce(lambda x, y: (x+y) if y <= 85.0 else (x-y), a, 0)
return fitness_1_temp
print (escolher())
Same solution, you only need to import the function of module functools .
