Custom ordering in Python

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Custom ordering in Python

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#1 by (1 votes)

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I have a list foo = ["BCB", "CAB", "CBC"] and a specific alphabetical order bar = "ACB" .

The result with this specific order should be resultado = ["CAB", "CBC", "BCB"]

How do I sort this list?

string python lista

asked by anonymous 17.02.2018 / 18:15

1 answer

Class diagram x Database doubts with json / array nesting

score 1 · Accepted Answer

Hello, you can use the following:

foo = ["BCB", "CAB", "CBC"]
bar = "ACB"
foo_new = sorted(foo, 
          key = lambda ordenar: [bar.index(i) if i in bar else ord(i) for i in ordenar])

Or this, which uses your desired order in a dynamic:

bar2 = {'A': 0, 'C': 1, 'B': 2}
foo2 = ["BCB", "CAB", "CBC"]
foo_new2 = sorted(foo2, 
           key=lambda ordenar: [bar2.get(i, ord(i)) for i in ordenar])

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