how to play letter by letter of a sentence in an array?

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how to play letter by letter of a sentence in an array?

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#1 by (1 votes)

0

Example: In the phrase naruto , the letter n of the frase vector is in the frase[0] position.

I want to put it in mat_cript position [0][0] . Not just her, the rest of the sentence too.

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <string.h>
#include <ctype.h>
#include <conio.h>
#include <time.h>

int main()

{
char frase[25];
    char mat_cript[i][j];
    int chave, tamanho_frase, cont,i,j;

    system("cls");

    printf("Digite a frase a ser criptografada : ");
    gets(frase);

    while(chave<1 || chave>25)
    {
        printf("Digite a chave a ser utilizada (<= 25) : ");
        scanf("%d",&chave);
        fflush(stdin);
    }

    tamanho_frase = strlen(frase);
    for(cont=0;cont<tamanho_frase;cont++)
        frase[cont] = frase[cont]+chave;

    printf("\n\nFRASE CRIPTOGRAFADA : %s",frase);
    getchar();

    for(i=0;i < tamanho_frase;i++){
        for(j=0;j< tamanho_frase;j++){
            mat_cript[i][j]=frase[i];
        }
    }

    for(i=0;i < tamanho_frase;i++){
        for(j=0;j< tamanho_frase;j++){
            printf(" %d°elemento da linha %d, coluna %d: %s",j+1;i+1;j+1;mat_cript[i][j]);
        }
    }

}

c string matriz

asked by anonymous 16.11.2018 / 17:05

1 answer

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score 1 · Accepted Answer

To do this, simply take control of the rows of your array and insert each character into the array separately. You must assign each character of the sentence to a position in the array.

In this example, the character - was placed in all positions of an array, then the character quantity of the phrase was counted and each character placed in a position in the array:

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <time.h> 

main(){
    char valid_chars[27];

    char mat_cript[10][10];
    char frase[10];

    srand(time(NULL));

    strcpy(valid_chars, "abcdefghijklmnopqrstuvwxyz");

    strcpy(frase, "naruto");
    int num = strlen(frase);

    for(int i = 0; i < 10; i++){
        for(int j = 0; j < 10; j++){
            int control = (rand() % 26);

            mat_cript[i][j] = valid_chars[control];;
        }
    }
    for(int i = 0; i < num; i++){
        mat_cript[5][i] = frase[i];
    }

    for(int i = 0; i < 10; i++){
        for(int j = 0; j < 10; j++){
            printf("\t%c", mat_cript[i][j]);
        }
        printf("\n");
    }
}

See working at Ideone .