I can not use the normal Ajax syntax in CakePHP . I've seen a few things about JsHelper , but I can not do what I want.
How can I call a action of controller by Ajax sending certain data and then receive the result of action in view ?
There is not much secret, this is the path you're following using JsHelper . First you need to include the helper in your Controller :
public $helpers = array('Js' => array('Jquery'));
And for example, you have a method so it will return a array containing some parameters:
public function ajax() {
$this->render(false, false);
debug($this->request->params);
}
The View corresponding to another Controller ( teste_ajax , for example) we will only put a button, passing two parameters, foo and bar :
echo $this->Js->submit('Enviar', array('update' => '#response', 'url' => array('action' => 'ajax', 'foo', 'bar')));
echo $this->Html->script('jquery');
echo $this->Js->writeBuffer(array('inline' => 'true'));
echo "<div id='response'></div>";
Note that I set to display my response on the #response element, which is my div of the last line.
See is clear and you can understand to be able to implement according to your needs.
I do not know about Cake, I work with Codeigniter, but it should not be very different. What I do is, in the action of ajax I call the controller and the simplest is to give an echo (it is not the most recommended, just for test) and the printed value of the echo I receive in the return of success. Something like this:
js:
$.ajax({
url: 'ajax/action',
type: 'GET',
data: {chave:valor},
success: function (retorn) {
$('#content').html(retorn); //colocar o retorno no #content
},
error: function () {
alert('Erro');
}
});
php:
class Ajax extends CI_Controller {
public function action()
{
echo "teste";
}
}
Hope it helps