I need help in a regular expression that matches (% ) in a string whose:
}
\ ) } at the end of the back line. I tried various combinations and I could not.
Thanks for the help, in advance!
I'll assume that regex flavor is similar to php , one of the most common.
I'll also assume that escaped characters are line breaks, something that the " . " operator does not capture, so you can use this regex here:
}(.|\n)*?}
Explanation:
} determines that it will only start capturing if a key is closed. ( declares the start of the catch group. .|\n causes it to catch any character that is not a line break, or a line break (in the end, any character). ) declares the end of the capture group. *? quantifying lazy , ensuring that it will stop the catch on the first occurrence of the keys' date, preventing it from capturing unnecessary things if there is more than one occurrence of {} in the code.
} sets key closure condition to end capture You can test it here