Hello friends, how are you?
In my database I have the date time like this: 2018-06-22 12:00:00
in the final html looks like this:
<input type="datetime-local" class="form-control" id="data_contratado" name="data_contratado" value="2018-06-22 12:00:00">
But in the end I can not display the value in the field.
Doing me a favor could you help me?
To cover any and all date from the bank I would do it this way:
$dataInput = $date->format('Y-m-d\TH:i:s');
that would meet the following situations
//data completa
$date = new DateTime('2018-06-22 12:00:00');
$dataInput = $date->format('Y-m-d\TH:i:s');
echo '<input type="datetime-local" value="'.$dataInput.'">';
//resultado 22/06/2018 12:00
//data incompleta
$date2 = new DateTime('2018-06-22');
$dataInput2 = $date2->format('Y-m-d\TH:i:s');
echo '<input type="datetime-local" value="'.$dataInput2.'">';
//resultado 22/06/2018 00:00
Notice that in the second case there is no space after the date day, thus invalidating your solution
str_replace(' ','T','2018-06-22')which will returndd/mm/aaa --/--
To test these codes online PHPTester
I was able to resolve it as follows:
str_replace(' ','T','2018-06-22 12:00:00')
But I do not know if it's the best way
You can use this way: $dateHtml = date("Y-m-d\TH:i:s", strtotime($date)); and add value in html.