Remote REST WebService in PHP receiving JSON via POST with problems

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Remote REST WebService in PHP receiving JSON via POST with problems

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#1 by (12 votes)

5

I have the following situation ...

A pure javascript client application that runs with node.js, where I send via a JSON post, as follows:

    doLoad = function (livrosList){
            var xmlhttp = new XMLHttpRequest();    
            xmlhttp.open("POST", "http://servidor_remoto/webservice/webs.php", true);
            xmlhttp.setRequestHeader("Content-Type", "application/json; charset=utf-8");  
            arqJson = JSON.stringify(livrosList);

        xmlhttp.send(arqJson);
    }

A Webservice in PHP that receives the listList books and stores your data in the MySQL database:

       include('LivrosList.php');
       header('Content-Type: application/json; charset=utf-8');
       header("access-control-allow-origin: *");

     $obj_php = json_decode(stripslashes($_POST['arqJson']));       
     if(empty($_POST['arqJson'])){
        return;
     }

    $livros = new Livros;

    foreach ( $obj_php as $liv ) { 
        $livros->insertLivros($liv->nome, $liv->numeropaginas);
    }

The problem is that $ _POST ['arqJson'] is not being recognized. I see that in the Apache log it is occurring that arqJson is not set. I do not know if it's because it's on a remote server. So how could I send this list of data to the webservice and store such data in the database? Thanks in advance for your help!

php rest javascript web-service post

asked by anonymous 15.01.2015 / 00:01

1 answer

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score 12 · Accepted Answer

The problem is that the WebService is sending the POST with Content-Type: application/json and PHP does not fill $_POST with the data sent in this way.

$_POST will only be automatically populated if Content-Type is application/x-www-form-urlencoded or multipart/form-data .

To read objects received in this POST you should do the following:

// lê o json diretamente dos dados enviados no POST (input)
$json = file_get_contents('php://input');
$obj_php = json_decode($json); // $obj_php agora é exatamente o objeto/array enviado pelo servidor

$livros = new Livros;

foreach ( $obj_php as $liv ) { 
    $livros->insertLivros($liv->nome, $liv->numeropaginas);
}

I've already broken my head with this same problem. Hope it helps!