How to select a String in column format? SQL SERVER

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How to select a String in column format? SQL SERVER

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#1 by (2 votes)

1

I have a STATUS field in a table with the following data:

VENDA,COMPRA,DEV.VENDA

I need to make a query in this field that the result is a column, where each row will be one of the strings between the ',' (VALUES).

For example:

VENDA

COMPRA

DEV.VENDA

sql-server string

asked by anonymous 22.05.2015 / 15:14

1 answer

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score 2 · Answer 1

I adapted a function that I found personal, thanks for the help.

create FUNCTION Split(@String varchar(MAX), @Delimiter char(1))       
returns @temptable TABLE (items varchar(MAX))       
as       
begin      
    declare @idx int       
    declare @slice varchar(8000)       

    select @idx = 1       
        if len(@String)<1 or @String is null  return       

    while @idx!= 0       
    begin       
        set @idx = charindex(@Delimiter,@String)       
        if @idx!=0       
            set @slice = left(@String,@idx - 1)       
        else       
            set @slice = @String       

        if(len(@slice)>0)  
            insert into @temptable(Items) values(@slice)       

        set @String = right(@String,len(@String) - @idx)       
        if len(@String) = 0 break       
    end   
return 
end

Query:

Select * from Split('A-B-C-D-E-F','-')

Output:

Items
-----
A
B
C
D
E
F