Based on the question link
I know I can use ${project.build.sourceDirectory} to access my source files directory. If I want to access the resource files directory, the resources , how do I? ${project.build.resources.resource.directory} did not work.
${project.build.resources[N].directory}
N = Index of your resource (ex: 0,1,2 and etc).
According to documentation , the default resource directory (aka resources) is located in:
src/main/resources
What would give us the possibility of access through the expression:
${basedir}/src/main/resources
However , you can specify a directory other than the default directory for features:
<project>
...
<build>
...
<resources>
<resource>
<directory>[seu-diretório]</directory>
</resource>
</resources>
...
</build>
...
</project>
In addition, you can still specify multiple resource directories:
<project>
...
<build>
...
<resources>
<resource>
<directory>src/main/recursos-1</directory>
</resource>
<resource>
<directory>src/main/recursos-2</directory>
</resource>
...
</resources>
...
</build>
...
</project>
Therefore, the expression for a resource directory is:
${project.build.resources[N].directory}
Where N is the index of your resource. Example:
${project.build.resources[0].directory}
${project.build.resources[1].directory}
...
This may raise another question: How do I know which directory will be associated with index 0, 1, 2, and so on?
There is the help: evaluate plugin that helps you test expressions.
Example:
<project>
...
<build>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-help-plugin</artifactId>
</plugin>
...
<resources>
<resource>
<directory>src/main/recursos-1</directory>
</resource>
<resource>
<directory>src/main/recursos-2</directory>
</resource>
...
</resources>
...
</build>
...
</project>
Testing (bash):
mvn help:evaluate -Dexpression=project.build.resources[0].directory | grep -v "\["
mvn help:evaluate -Dexpression=project.build.resources[1].directory | grep -v "\["
Although the plugin documentation specifies the -q (quiet) and -DforceStdout options, I was not successful in displaying only the result of the expression $ {project.build. resources [0] .directory}, so I used grep -v to filter the output.