How to save an image generated by php gd?

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How to save an image generated by php gd?

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#1 by (2 votes)

2

I'm trying to use jcrop + php gd to make image cuts and save in another directory but I do not know what the problem with my code is:

<?php

if ($_SERVER['REQUEST_METHOD'] == 'POST')
{
    $targ_w = $targ_h = 150;
    $jpeg_quality = 90;

    $src = 'teste/imagem.jpg';
    $img_r = imagecreatefromjpeg($src);
    $dst_r = ImageCreateTrueColor( $targ_w, $targ_h );

    imagecopyresampled($dst_r,$img_r,0,0,$_POST['x'],$_POST['y'],
    $targ_w,$targ_h,$_POST['w'],$_POST['h']);

    header('Content-type: image/jpeg');
    imagejpeg($dst_r,null,$jpeg_quality);

    exit;
}

?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
  "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html>
    <head>

        <script src="http://deepliquid.com/Jcrop/js/jquery.Jcrop.min.js"></script><scriptsrc="../js/jquery.Jcrop.js"></script>
        <link rel="stylesheet" href="../css/jquery.Jcrop.css" type="text/css" />
        <link rel="stylesheet" href="demo_files/demos.css" type="text/css" />

        <script language="Javascript">

            $(function(){

                $('#cropbox').Jcrop({
                    aspectRatio: 1,
                    onSelect: updateCoords
                });

            });

            function updateCoords(c)
            {
                $('#x').val(c.x);
                $('#y').val(c.y);
                $('#w').val(c.w);
                $('#h').val(c.h);
            };

            function checkCoords()
            {
                if (parseInt($('#w').val())) return true;
                alert('Please select a crop region then press submit.');
                return false;
            };

        </script>

    </head>

    <body>

    <div id="outer">
    <div class="jcExample">
    <div class="article">

        <h1>Crop jQuery</h1>

        <img src="teste/imagem.jpg" id="cropbox" />
        <form action="crop.php" method="post" onsubmit="return checkCoords();">
            <input type="hidden" id="x" name="x" />
            <input type="hidden" id="y" name="y" />
            <input type="hidden" id="w" name="w" />
            <input type="hidden" id="h" name="h" />
            <input type="submit" value="Crop Image" />
        </form>

    </div>
    </div>
    </div>
    </body>

</html>

php javascript html jquery jcrop

asked by anonymous 21.07.2015 / 17:40

1 answer

Add typed values without using array Search SQL database in a text saved by TinyMCE

score 2 · Answer 1

use imagepng($imagem, $NomeDeSaida); for png or imagejpeg($imagem, $NomeDeSaida); for jpg

if ($_SERVER['REQUEST_METHOD'] == 'POST')
{
    $targ_w = $targ_h = 150;
    $jpeg_quality = 90;

    $src = 'teste/imagem.jpg';
    $img_r = imagecreatefromjpeg($src);
    $dst_r = ImageCreateTrueColor( $targ_w, $targ_h );

    imagecopyresampled($dst_r,$img_r,0,0,$_POST['x'],$_POST['y'],
    $targ_w,$targ_h,$_POST['w'],$_POST['h']);
    imagejpeg($dst_r, $NomeDeSaida);

//header('Content-type: image/jpeg');
//imagejpeg($dst_r,null,$jpeg_quality);

    exit;
}