How to get only a part of a string from a pattern?

Question

How to get only a part of a string from a pattern?

Navigation

#1 by (2 votes)

2

I have a string in Lua language. I want to get only the filename part through match ( 403.htm.en ).

Example:

var=[[Content-Disposition: attachment; filename="403.htm.en"
     Content-Type: text/plain; name='403.htm.en'
     Content-Transfer-Encoding: BASE64
    ]]
filename = string.match(var,"filename(.+)")
print("filename", filename)

string regex lua

asked by anonymous 30.07.2015 / 18:59

1 answer

Redirection in CodeIgniter Is there any way to translate the error messages produced by PHP?

score 2 · Accepted Answer

I do not know the most reliable form but this works:

var=[[Content-Disposition: attachment; filename="403.htm.en"
     Content-Type: text/plain; name='403.htm.en'
     Content-Transfer-Encoding: BASE64
    ]]
filename = string.match(var,"filename=\"(.+)\"")
print("filename = ", filename)

See running on ideone .

You had to put the delimiters wherever you want the text to begin and end.