jQuery does not recognize .click event of a class added with append [duplicate]

Folks, I can not get the .click event of a button that is added with the append command to work.

Here is the function that contains append:

    function mostrarUploads(nome, tabela) {

    var $table = $(tabela);
    $table.html("");

    //apenas atualiza as categorias caso esteja abrindo o collapse, nunca quando está fechando
    showPleaseWait();

    $.ajax({
      url: "/painel/mostrarUploadsCategorias",
      method: 'POST',
      data: {_token: jQuery(".token").val(), nome: nome},

      success: function(e) {

        e.forEach(function(item, indice) {
            //remove o diretório da string e só deixa o nome final do arquivo
            var nomeArquivo = item.replace('public/painel/categorias/' + nome + "/", ""); 
            $table.append("<tr><td>" + nomeArquivo + "</td> <td><a class='btn btn-success' href=\"/painel/fazerDownload/" + nome + "/" + nomeArquivo + "\">Download</a> <button type='button' class='btn btn-danger excluirUpload' data-diretorio=\"" + item + "\">Excluir</button></td></tr>");
        });
      }
    }).done(function() {        //só abre o modal assim que terminar a requisição ajax
        hidePleaseWait();
    });

}   

And the click event of the button:

    jQuery(function() {

... algumas outras funções...

        $(".excluirUpload").click(
            function() {
                alert('excluindo');
                //carregar os uploads desta categoria
                var diretorio = $(this).data('diretorio');
                var $table = $(this).closest('.categoria').find("tbody");

                excluirUpload(diretorio, $table);
            }
        );
    });

Would it be because of .append, this .click event is not recognizing the class of this button ?? How to proceed ??

Another thing I tried was to call a function with onclick, but I need to pass this $ table as a parameter and, when I get in the function as a parameter, if I print, my return is [Object object]. Either approach would be useful, but I could not make either of them work.

Thank you!