I made this little code so that it asked for a user and a password. If the data were the same as those defined within the code, show a "success", if the user is different from what is placed in the code, ask the user again.
I tried to use the while repeat structure, but I'm not using it correctly.
import getpass
user = str(input('Usuário: '))
def login():
while(user!='admin'):
user = str(input('Usuário: '))
if (user=='admin'):
passwd = getpass.getpass('Senha: ')
else:
login()
I do not know if I understand the question, but come on:
View the code running on rel.it.
import getpass
def login():
usr = 'Admin'
while True:
user = str(input('Usuário: '))
if user != usr:
print('Usuário inválido')
else:
print ('Senha: ')
getpass.getpass('Senha: ')
print ('ok')
break
login()
Usuário: afasdfasf
Usuário inválido
Usuário: Admin
Senha:
master
ok
import getpass
user = str(input('Usuário: ')) # user é variavel global
def login(): # user não existe dentro de login()
while(user!='admin'):
user = str(input('Usuário: ')) # essa linha deveria estar identada pra ficar dentro do loop while
if (user=='admin'):
passwd = getpass.getpass('Senha: ')
else:
login()
I made some punctual comments in your original code, below is the code that I imagine you have tried to do.
import getpass
user = str(input('Usuário: '))
def login(user): # user passado por parametro pra poder ser acessado dentro da função
while(user!='admin'):
user = str(input('Usuário: ')) # informação dentro do loop while identada corretamente
if (user=='admin'):
passwd = getpass.getpass('Senha: ')
else:
login(user) # variavel user sendo passada por parametro pra função login.
passwd = getpass.getpass('Senha: ') # recebe passwd após sair da função
I imagine the end result would be this. Note that if the objective is to print on the screen the string Senha: before the user enters the password, you will have to do something like @Sidon did, because the getpass.getpass function does not print the string passed by parameter.