Hello.
I have these two dates:
var dtPartida = "20170620 11:20";
var dtChegada = "20170620 16:40";
You need to find out the difference in hours between these dates in the case and 5 hours and 20 minutes.
I need it to return like this:
5h 20m
and not like this:
05:20
Manually with javascript, you can create a date from the string, taking separately year, month, day, minute and second, and then calculate the difference between the dates (and minutes and seconds).
Example
var dtPartida = "20170620 11:20";
var dtChegada = "20170620 16:40";
var date1 = new Date(dtPartida.slice(0,4), dtPartida.slice(4,6),dtPartida.slice(6,8), dtPartida.slice(9,11), dtPartida.slice(12,14)),
date2 = new Date(dtChegada.slice(0,4), dtChegada.slice(4,6),dtChegada.slice(6,8), dtChegada.slice(9,11), dtChegada.slice(12,14));
var diffMs = (date2 - date1);
var diffHrs = Math.floor((diffMs % 86400000) / 3600000);
var diffMins = Math.round(((diffMs % 86400000) % 3600000) / 60000);
var diff = diffHrs + 'h ' + diffMins + 'm';
console.log(diff);A powerful javascript library for handling dates Moment.js
var dtChegada = "20/06/2017 16:40:00";
var dtPartida = "20/06/2017 11:20:00";
var ms = moment(dtChegada,"DD/MM/YYYY HH:mm:ss").diff(moment(dtPartida,"DD/MM/YYYY HH:mm:ss"));
var d = moment.duration(ms);
var s = Math.floor(d.asHours()) + moment.utc(ms).format(":mm:ss");
console.log(s);<script type="text/javascript" src="//cdnjs.cloudflare.com/ajax/libs/moment.js/2.4.0/moment.min.js"></script>To return in the requested format in comment 5h 20m just act on the variable
s
var s = Math.floor(d.asHours()) + "h" + moment.utc(ms).format(" mm") +"m";
var dtChegada = "20/06/2017 16:40:00";
var dtPartida = "20/06/2017 11:20:00";
var ms = moment(dtChegada,"DD/MM/YYYY HH:mm:ss").diff(moment(dtPartida,"DD/MM/YYYY HH:mm:ss"));
var d = moment.duration(ms);
var s = Math.floor(d.asHours()) + "h" + moment.utc(ms).format(" mm") +"m";
console.log(s);<script type="text/javascript" src="//cdnjs.cloudflare.com/ajax/libs/moment.js/2.4.0/moment.min.js"></script>Assuming the times you mentioned before editing the question:
var dtChegada = "16:40";
var dtPartida = "11:20";
var ms = moment(dtChegada,"HH:mm").diff(moment(dtPartida,"HH:mm"));
var d = moment.duration(ms);
var s = Math.floor(d.asHours()) + "h" + moment.utc(ms).format(" mm") +"m";
console.log(s);<script type="text/javascript" src="//cdnjs.cloudflare.com/ajax/libs/moment.js/2.4.0/moment.min.js"></script>In case the dates are in the format of Lucas Costa's response
var dtChegada = "20170620 16:40";
var dtPartida = "20170620 11:20";
var ms = moment(dtChegada,"DD/MM/YYYY HH:mm:ss").diff(moment(dtPartida,"DD/MM/YYYY HH:mm:ss"));
var d = moment.duration(ms);
var s = Math.floor(d.asHours()) + "h" + moment.utc(ms).format(" mm") +"m";
console.log(s);<script type="text/javascript" src="//cdnjs.cloudflare.com/ajax/libs/moment.js/2.4.0/moment.min.js"></script>You can test for the minutes or seconds of the hours:
function verificarDiferencaHorario(inicialMin, finalMin) {
var totalMin = Number(finalMin - inicialMin);
console.log(Math.trunc(totalMin / 60).toString() + ":" + (totalMin % 60).toString());
}
Assuming the times you mentioned:
function verificarHorario() {
var inicial = "11:20", final = "16:40";
var splInicial = inicial.split(":"), splFinal = final.split(":");
var inicialMin = (Number(splInicial[0] * 60)) + Number(splInicial[1]);
var finalMin = (Number(splFinal[0] * 60)) + Number(splFinal[1]);
verificarDiferencaHorario(inicialMin, finalMin);
}
The same goes for days: the last conversion in minutes and the checkDifferentialTime function returns the difference in hours and minutes.