I have the following content:
123|321|1234\|56\|teste\||123
I would like to make a regex replace that would replace all | with line break and ignore | escaped with \ , so I would like to get the following return:
123
321
1234|56teste|
123
If someone has an alternative that is not regex , it works.
I found the answer in the stack overflow , but I'll translate here:
You can use this regex:
(?:\.|[^\|\]++)*
To get all content between pipes :
List<String> matchList = new ArrayList<String>();
try {
Pattern regex = Pattern.compile("(?:\\.|[^\|\\]++)*");
Matcher regexMatcher = regex.matcher(subjectString);
while (regexMatcher.find()) {
matchList.add(regexMatcher.group());
}
Explanation:
(?: # Combina se...
\. # qualquer caracter escapado
| # ou...
[^\|\]++ # qualquer caracter exceto **|**
)* # repita inúmeras vezes
I would use a more straightforward translation than was stated: any | as long as it is not preceded by \ . This in regex is:
(?<!\)\|
With this, you can do this substitution on a single line:
"123|321|1234\|56\|teste\||123".replaceAll("(?<!\\)\|", "\n");