Divide a string with empty spaces

The strtok method, used to break a string, after passing its string a single time per parameter, just put NULL ou 0 in the first parameter, so the method will return the parts of the string. Use string.h

char *buff = "minha string com espaço";
char *word = strtok(buff," ");
int x=0;
while(word){
    puts(word);
    word = strtok(NULL, " ");
    x++;
}

The strtok function separates a string into "chunks", or tokens , according to some used expression.

Function prototype: char* strtok(char* str, const char* delimiters);

So a simple solution to your problem would be something like:

#include <stdio.h>
#include <string.h>

int main(int argc, char* argv[]) {
    char string[] = "1444771699,Andre Alves,SAQUE,-500.00,,200";
    printf("String: %s\n", string);
    char* token;
    token = strtok(string, ",");
    while (token != NULL) {
        printf("%s\n", token);
        token = strtok(NULL, ",");
    }
    return 0;
}

Considering your entry as 1444771699,Andre Alves,SAQUE,-500.00,,200 , executing the above code will result in the output below < 1444771699 Andre Alves SAQUE -500.00 200

You can then allocate the output below in an array of strings if needed according to your application.

You can format the character string by character.

Example:

#include <iostream>
#include <cstdio>
#include <cstdlib>

using namespace std;

int main() {
    string s = "1444771699,Andre Alves,SAQUE,-500.00,,200";
    int qtd = 1;

    printf("string %d: ", qtd);
    for (int i = 0; i <  s.length(); i++)
        if ( s[i] != ',')
            printf("%c", s[i]);
        else if ( s[i] == ',') {
            qtd++;
            printf("\nstring %d: ", qtd);
        }

    return 0;
}

I assume the problem is empty fields, which strtok() does not recognize. In Linux, we have the function strsep() , which was created precisely to solve the limitation of strtok() :

#include <string.h>
char *strsep(char **stringp, const char *delim);