def repita():
x = 2
while n % x != 0:
x += 1
repeat()
while n > 1:
n = n / x #aqui se encontra o primeiro problema, já que "n" não é reconhecido fora da função
x += 1
if n % x != 0:#mesmo problema de antes
repita() #aqui a função se repetiria aumentando o valor do "x"
My question is how to use return so that "n" and "x" are recognized and I can work with them.
This is because of the scope rules.
x is created inside the function repeat, and ceases to exist once the function terminates.
To get the final value of x you need to write something like
def repita:
x = 2
return x
x2 = repita()
The return returns the value of x out of the scope of the function, and this value is assigned to the variable x2.
It is not recommended to have a variable that is going to be accessed throughout the program (global variable), but it is possible.
x = 2
def repita:
x = 5
x = x + 5
Since the initial definition is outside the function, the value is changed inside and outside the function.