Send form without updating the page and show hidden div [closed]

Navigation
-2
Well, I have a form that saves the data in the database and it works fine, but I need to click on the form to send a% hidden% with the list of data saved in the database (I already have the right list) big problem even and div appears as soon as I submit the form without updating the page, I already tried some javascript and jQuery codes that did not work. Can anyone help me?

This and the form to enter the data: 

<form action="" method="post" id="meufrm" enctype="multipart/form-data">
<fieldset>

    <legend style="color: #ffffff" class="btn btn-inverse">Cadastro </legend>



    <label for="nome" style="color: #000"><strong>Nº da Venda :</strong> </label>
    <input type="number" name="num_venda"></br></br>


    <div id="datavenda">
        <label for="nome" style="color: #000"><strong>Data :</strong> </label>
        <input type="date" name="data_venda"></br></br>
    </div>


    <div id="placavenda">
        <label for="nome1" style="color: #000"><strong>Placa :</strong> </label>
        <input type="text"  name="placa" ></br></br>
    </div>

    <div id="kmvenda">
        <label for="imagem" style="color: #000"><strong>KM : </strong></label>
        <input type="number"  name="km"></br></br>
    </div>

    <?php

    mysql_connect('127.0.0.1','root','');

    //escolher a base de dados
    mysql_select_db('mecanica');
    $query='Select * from produtos';

    ?>



    <label for="produtos" style="color: #000"><strong>Produto : </strong></label>
    <select name="produtos">
        <?php

        $resultado=mysql_query($query);

        while($linha=mysql_fetch_array($resultado))
        { 

            echo '<option  value="' . $linha['id_produto'] . '">' . $linha['produtos'] . '</option>';
        }
        echo '</select>';
        ?>

    </select><br><br>


    <div id="servicovenda">
        <?php
        mysql_connect('127.0.0.1','root','');


        mysql_select_db('mecanica');

        $query='Select * from servicos';

        ?>



        <label for="servicos" style="color: #000"><strong>Serviços : </strong></label>
        <select name="servicos">
            <?php

            $resultado=mysql_query($query);


            while($linha=mysql_fetch_array($resultado))
            {

                echo '<option  value="' . $linha['id_servico'] . '">' . $linha['servicos'] . '</option>';
            }
            echo '</select>';
            ?>
        </select><br><br>
    </div>

           <div id="enviarvenda">
        <input type="submit" class="btn btn-inverse" value="Enviar" name="send" >

        <a href="listadevendas.php" class="btn btn-inverse" >Cancelar</a>
    </div>

</fieldset>

As soon as I send the data I would have to list the results of the hidden div on the same page

    
asked by anonymous 03.12.2015 / 13:02

1 answer

0

I'd advise sending the data to the server-side via AJAX , so you control better the behavior of your page, and does not give that reload annoyance with the submit of the form. 

$('#divOculta').hide();
function salvarExemplo(){

  $.ajax({
    url: "index.php", //Form que recebe o "submit"
    data: {id:1,nome:'Ragnar'} //Aqui vai seus parametros
  }).success(function(data) {
    $('#divOculta').html(data.lista); //Aqui vc recebe o retorno e monta sua lista na div oculta

    //Caso queira mostrar a div oculta.
    $('#divOculta').show();

  });
}

Ajax is the way of strength, learn to use and respect strength. ;-)

    
03.12.2015 / 13:19
Generate code (like option value) Problems installing Visual Studio 2015 Community