How to replace vowels by @ [closed]

Well, I thought of this solution:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
char vogais[] = {'a','A','e','E','i','I','o','O','u','U'};
char texto[20] = "stAckovErflow";
int i,j;

//substituindo as vogais
for(i=0; i < strlen(texto); i++)
{
    for(j=0; j < strlen(vogais); j++)
    {
        if(vogais[j] == texto[i])
        {
            texto[i] = '@';
        }
    }
}

//invertendo a String
strrev(texto);
//imprimindo no console
printf("%s\n", texto);

system("pause");
return 0;
}

I hope I have helped!

Strings in C are character arrays. Use for with a i counter to move through each position. At each iteration of for , you get the letter at the i position and compare it with 'a' , 'e' , 'i' , 'o' , and 'u' . If one of these comparisons is true (use || ), then you change the character in the string by a '@' . You will have to compare both the lower and upper case vowels.

After you use another for to invert the string, it will go through i positions from the beginning of the string to the middle, then you change the character from the i to the n - i - 1 position, where n is the length of the string.

To replace the vowels with '@', we go through array of characters (str), for each character check if it is equal to a vowel (str [i] == vowels [v]), assigning the @ in the index which is the vowel (str [i] = '@')

In the example below, the result is 'st @ ck @ v @ rfl @ w' for str="stackoverflow";

int main()
{

    char vogais[] = {'a','e','i','o','u'};
    char str[20] = "stackoverflow";
    for(int i =0; i<strlen(str); i++){
        int vogal=0;
        for(int v =0; v<5; v++){
            if(str[i] == vogais[v]) vogal= 1;
        }
        if(vogal == 1){
            str[i] = '@';
        }
    }
    printf("%s",str);
    return 0;
}