I have text saved in a string and need to copy a portion of this text to the find a certain word in it.
Eg: I need to remove my name and age from this text, I know they always come after: and in quotation marks.
String texto = "Meu nome: "+ "Mariane Teixeira" + ", Minha idade: "+ "22";
//resposta
String nome = "Mariane Teixeira"
String idade = "22"
I can use FLAG as: or "" or the word "name" and "age" and copy what comes after them, but I do not know how to do this using java code.
You can use a regular expression to extract the values of your String :
([^,\:]+)\:([^\,]+)
This regular expression will look for any sequence of 1 or more characters that are not , nor : ( ([^,\:]+) ) followed by : ( \: ) that has any sequence of one or more characters that do not contain , ( ([^\,]+) ). In%% we escaped the special characters of the regular expression with two bars ( Java ). So I came up with the following method that turns your \ into String :
public static Map<String, String> separar(String texto) {
String regex = "([^,\:]+)\:([^\,]+)";
Map<String, String> resultado = new HashMap<>();
Pattern parte = Pattern.compile(regex);
Matcher matcher = parte.matcher(texto);
while (matcher.find()) {
String chave = matcher.group(1);
String valor = matcher.group(2);
resultado.put(chave.trim(), valor.trim());
}
return resultado;
}
You can test the method with your Map as follows:
public static void main(String[] args) {
String texto = "Meu nome: Mariane Teixeira, Minha idade: 22";
Map<String, String> valores = separar(texto);
valores.forEach((chave, valor) -> System.out.println(chave + ": " + valor));
}
The value printed on String would read as follows:
Meu nome: Mariane Teixeira Minha idade: 22
Some comments:
Your console is very much like the rating of a String , although not% represents% valid%. So, consider using it.
In your example you used the code JSON to generate the JSON . The result would be "Meu nome: "+ "Mariane Teixeira" + ", Minha idade: "+ "22" . If you want to put the values in quotation marks the assignment should be String .
A very lazy way to solve:
String text = "Meu nome: \"Mariane Teixeira\", Minha idade: \"22\"";
String [] textArray = text.split("\"");
System.out.println(Arrays.toString(textArray));
System.out.println("Meu nome: " + textArray[1]);
System.out.println("Minha idade: " + textArray[3]);