In the string transp, it was to appear all 4 names, however, only the last [closed]

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In the string transp, it was to appear all 4 names, however, only the last [closed]

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#1 by (3 votes)

-1

#include <iostream>

using namespace std;

void texto();
void soma(int n1, int n2);
int soma2(int n1, int n2);
void tr(string tra[4]);

int main(){
    int res;
    string transp[4]=("carro","moto","barco","aviao");

    soma(15,5);
    res=soma2(175,25);

    cout << "valor de res: " << res << "\n";

    tr(transp);

         return 0;
}

void texto(){
    cout << "canal fessor bruno\n";
}

void soma(int n1, int n2){
    cout << "soma dos valores: " << n1+n2 << "\n";
}

int soma2(int n1, int n2){
    return n1+n2;
}

void tr(string tra[4]){
    for(int i=0; i<4; i++){
        cout << tra[i] << "\n";
    }
}

c++

asked by anonymous 09.02.2018 / 03:35

1 answer

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score 3 · Answer 1

In the way that you are initializing the array the problem is in the use of parentheses instead of keys.

For this case the correct boot is:

string transp[4]={"carro","moto","barco","aviao"};

You can see the code working here

When you use the parentheses in place of braces you are grouping expressions and using the comma (comma) operator. This operator is not very well known and it serves to separate two or more expressions (in this case a string is an expression) and the expressions are evaluated one by one from left to right and the value of the entire expression is the value of the last expression in the list (in your case the value of the expression is "airplane", so it puts in all positions.)

For more details you can check:

Built-in comma operator

Wikipedia comma operator