Function inputmask () for cpf and cnpj

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Function inputmask () for cpf and cnpj

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#1 by (3 votes)
#2 by (0 votes)

-1

I'm using the Inputmask plugin, the following JS

$("input[id*='cpfcnpj']").inputmask({
    mask: ['999.999.999-99', '99.999.999/9999-99'],
    keepStatic: true
});

My input is catching the cpf mask , but gets caught in it. When it reaches the 11 digits, it does not enable the cnpj mask.

jquery

asked by anonymous 05.04.2017 / 20:42

2 answers

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score 3 · Answer 1

I did not quite understand your problem. Using this InputMask library , your code works perfectly.

See an example below.

$("input[id*='cpfcnpj']").inputmask({
  mask: ['999.999.999-99', '99.999.999/9999-99'],
  keepStatic: true
});

<script src="https://code.jquery.com/jquery-1.10.0.min.js"></script><scriptsrc="https://rawgit.com/RobinHerbots/Inputmask/3.x/dist/jquery.inputmask.bundle.js"></script>


<input id="cpfcnpj" placeholder="CPF ou CNPJ" />

score 0 · Answer 2

Well, you do not need a plugin for this:

function mascaraMutuario(o,f){
    v_obj=o
    v_fun=f
    setTimeout('execmascara()',1)
}

function execmascara(){
    v_obj.value=v_fun(v_obj.value)
}

function cpfCnpj(v){

    //Remove tudo o que não é dígito
    v=v.replace(/\D/g,"")

    if (v.length <= 14) { //CPF

        //Coloca um ponto entre o terceiro e o quarto dígitos
        v=v.replace(/(\d{3})(\d)/,"$1.$2")

        //Coloca um ponto entre o terceiro e o quarto dígitos
        //de novo (para o segundo bloco de números)
        v=v.replace(/(\d{3})(\d)/,"$1.$2")

        //Coloca um hífen entre o terceiro e o quarto dígitos
        v=v.replace(/(\d{3})(\d{1,2})$/,"$1-$2")

    } else { //CNPJ

        //Coloca ponto entre o segundo e o terceiro dígitos
        v=v.replace(/^(\d{2})(\d)/,"$1.$2")

        //Coloca ponto entre o quinto e o sexto dígitos
        v=v.replace(/^(\d{2})\.(\d{3})(\d)/,"$1.$2.$3")

        //Coloca uma barra entre o oitavo e o nono dígitos
        v=v.replace(/\.(\d{3})(\d)/,".$1/$2")

        //Coloca um hífen depois do bloco de quatro dígitos
        v=v.replace(/(\d{4})(\d)/,"$1-$2")

    }

    return v
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.0/jquery.min.js"></script><inputtype="text" class="form-control"  id="user_cpf" name="user_cpf" placeholder="" maxlength="18" onkeypress='mascaraMutuario(this,cpfCnpj)' onblur='clearTimeout()' required data-error="Informe seu CPF">