I would like to know the following how do I give return in a function created by me in a situation below. For always returns undefined object, but when I give an alert it returns the normal object.
function jjson(url){
var result;
$.getJSON( url, function(data) {
alert(data)
result = data;
});
return result;
}
ATT
This function will always give return undefined because AJAX is asynchronous.
You need to use a callback to do what you need when the server response arrives. You can use it like this:
function jjson(url, callback){
$.getJSON( url, callback);
}
and then call the function by passing to the callback what you want to do:
jjson('google.com', function(result){
alert(result);
});
In practice this can be simplified if you put what you want to do directly in getJSON ...
$.getJSON(url, function(data) {
gerarGrafico(data); //por exemplo
});
Well, this code is only run when the server data has arrived.