I have this:
l=['Car 8', 'Bike 5', 'Train 10']
And I would like to have something like this:
[('Car','8'), ('Bike','5'), ('Train','10')]
How could you make a list of strings into something like a list of strings tuples?
I'm new to Ubuntu and I'm learning Python.
I have installed Pyhton 2.7.12 on my pc and would like to know how I can upgrade to version 3.
I'm doing a course where I need to make use of a lib.
import urllib.request
But the following er...
I would like to know the order of evaluation of this expression in Python:
if 'a' <= c <= 'z': # c é uma variável de tipo 'chr'
print("Ronal... D'oh!")
The code I'm using is:
import time
def divisores(num):
for i in range(1, int(num/2+1)):
if num % i == 0:
yield i
yield num
inicio = time.time()
d = divisores(47587950)
[print(i) for i in d]
print("Fim da execuçã...
I have a network dump (PCAP file) containing slowloris attacks:
ThefollowingscriptwillshowthenumberofconnectionspersecondtoIP192.168.1.2onport80:tcpdump-qns0-A-r1.pcaphost192.168.91.5andport80|sed-une's/^\(.\{8\}\).*IP\(.*\)\.[0-9]\+>192.168...
In Python:
How to convert screen coordinates to Cartesian coordinates, where there may be positive and negative points and the center of the screen is (0,0)?
I found things about a module called mysqldb, but I did not find documentation available at docs.python.org
Please disregard responding with frameworks such as Django.
How do I make a function to determine the smallest string in a list by ignoring spaces?
For example, when typing:
menor_elemento(["joão", " a ", "arrozz"])
The output should return "a" (without spaces), because it is the smallest strin...