listasIguais :: (Eq a) => [a] -> [a] -> Bool
listasIguais [] p = False
listasIguais p [] = False
listasIguais (x: xs) (y:ys) = x == y && (listasIguais xs ys)
listasIguais [(2,4),(4,6),(8,9)] [(1,4),(2,6),(4,9)]
False
This...
asked by
25.12.2017 / 14:46