Error executing program in C

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Error executing program in C

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#1 by (0 votes)

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I have to create a movie signup program, however when I run the program and it error and I do not know why it does not run, can you help me?

#include <stdio.h>
#include <locale.h>
#include <string.h>
#include <stdlib.h>

int main()

{
    struct informacao_sobre_os_filme
    {
       int ano_de_lancamento, faixa_etaria; 
       double duracao;
       char nacionalidade[200], nome_do_filme[200], genero[200];

    };

    struct informacao_sobre_os_filme;

    printf("CADASTRMENTO DE FILMES: \n");
    printf("Nome do filme: \n");
    scanf("%c", &nome_do_filme);
    return 0;
}

c

asked by anonymous 05.11.2017 / 23:22

1 answer

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score 0 · Answer 1

You have several issues with the code that appears.

%c is for reading a caretere. To read a string you must use %s
The declaration of a variable of type type struct informacao_sobre_os_filme; is left without the name of the variable.
The structure should be declared before main as convention and so that it can be used by various functions.

Correcting all this would look like this:

struct informacao_sobre_os_filme {
    int ano_de_lancamento, faixa_etaria;
    double duracao;
    char nacionalidade[200], nome_do_filme[200], genero[200];
};

int main(){
    struct informacao_sobre_os_filme filme1; //agora variavel chamada filme1

    printf("CADASTRMENTO DE FILMES: \n");
    printf("Nome do filme: \n");
    scanf("%s", filme1.nome_do_filme); //ler para o filme1 no campo nome_do_filme
    return 0;
}

Note that since nome_do_filme is an array of characters, it is already technically pointer to the first one, so it does not take & to scanf .

If you want you can even use a more robust form of reading that would be with fgets . With fgets can read more than one word and ensure that it does not read more than the space it allocated, which would in this case be 200 characters:

...
printf("Nome do filme: \n");
fgets(filme1.nome_do_filme, 200, stdin);
...