REFERENCE URL + VIA GET PARAMETERS

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How can I pass a URL that looks like this?

I want to leave something like this:

link #comments? approved = true

I know this way below, it works correctly the 2:

link ? approved = true

link #comments

But I wanted to send the 2 parameters via url, is it possible?

The goal of this url is, return to the page for the id comments E and receive a $ _GET ["approved" p>

OBS: ignore this, link I just picked it up complement my example.

    
asked by anonymous 06.01.2018 / 15:37

1 answer

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Solution

link

I did not know that & it worked for that case.

OBS: Do I delete the topic or keep it?

    
06.01.2018 / 15:42