As I have in the code gives me the error of
void can not be deferenced
In the part of nextInt() in the last two lines and with so many attempts I've already done I ended up staying like this. The latitude can not be outside [-9.5, -6.2] degrees and the longitude [36.8.42.2]
Random randomLongitude = new Random();
Random randomLatitude= new Random();
randomLatitude.setSeed((long)-9.5).nextInt((int)-6.2);
randomLongitude.setSeed((long)36.8).nextInt((int)42.2);
The error you get is because the setSeed method is void and therefore does not return any value which means that you can not .nextInt() then void .
randomLatitude.setSeed((long)-9.5).nextInt((int)-6.2);
//---------------------------------^ aqui
This setSeed method is used to define the random start point, also called random seed. It is useful only when you want to be able to reproduce certain random outputs in a deterministic way. In your case you also do not need to create two Random objects because with only one you can generate as many random numbers as you like.
If you want the numbers to go out at a specific interval, you need to multiply the number that exits by máximo-minimo and then add minimo :
Random random = new Random();
double randomLongitude = random.nextDouble() * (42.2-36.8) + 36.8;
Analyzing this last line we see that:
[0,1) with nextDouble . 42.2-36.8 , thus giving a number in the range 5.4
[0-5.4) we get the interval of 36.8
You can even create a function to simplify:
static Random random = new Random();
public static double aleatorioEntre(double min, double max){
return random.nextDouble() * (max-min) + min;
}
public static void main(String[] args) {
double randomLatitude = aleatorioEntre(-9.5, -6.2);
double randomLongitude = aleatorioEntre(36.8, 42.2);
}