I'm learning Java and I came across the need for the in operator. For example:
I have a vector ( v = {1,2,3,4,6} ) and I want to see if the 5 is in this vector (not in this case).
In python it would be v = [1,2,3,4,6] - 6 in v , then it would return False . I want to do this in Java, but do not find the operator that works.
How do I do this in java?
Using java-8, you can verify through the API Streams :
int[] a = {1,2,3,4};
boolean contains = IntStream.of(a).anyMatch(x -> x == 5);
See a test on ideone
Without using streams, this is also possible:
public static void main (String[] args)
{
int[] number = {1, 2, 3, 4};
if(contains(number, 5)){
System.out.println("Contem o numero 5");
}else {
System.out.println("Nao contem o numero 5");
}
}
public static boolean contains(final int[] array, final int v) {
boolean result = false;
for(int i : array){
if(i == v){
result = true;
break;
}
}
return result;
}
Also working on ideone .
This operator you are looking for is the contains ". The purpose of it is exactly the one you want.
If you change your array by a Set or List and the solution is simple. For this, you can use the asList to turn your array into a list:
List<Integer> lista = Arrays.asList(1, 2, 3, 4, 6);
System.out.println(lista.contains(5)); // false
System.out.println(lista.contains(4)); // true