In Java:
public class Teste extends Testando
{
private String nome;
private int numero;
public Teste(String teste, String nome, int numero)
{
super(teste);
this.nome = nome;
this.numero = numero;
}
}
What is the command corresponding to super() in C++ ?
You explicitly call the class name, because in C ++ there is multiple inheritance and may have more than one ancestor. In a rough way this would be it:
class Teste : public Testando {
String nome;
int numero;
public:
Teste(String teste, String nome, int numero) : Testando(teste) {
this.nome = nome;
this.numero = numero;
There is no direct relationship in C ++.
You can do something similar if you create a super typedef for all classes that want to use this feature, as in the case below:
class Derivada: public Base
{
private:
typedef Base super; // não deve ser público porque cada classe pode
// ter apenas uma classe super
} ;
And then you could use super in place of the base class name, as in the example:
super::meumetodo();
However, we do not recommend abusing this feature. In C ++ there is the possibility of multiple inheritance and this would already complicate the solution and could cause confusion.