If a char array is already a pointer, why declare a pointer to the array?
And what's the difference between char exemplo[10] and char *exemplo[10] ?
Why declare pointer to array if arrays are already pointers?
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asked by anonymous 08.10.2015 / 03:19
2 answers
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A char array (or other type) is NOT a pointer.
An array is an array; a pointer is a pointer (see c-faq section 6 ).
When an array is used as a value, it is converted to a pointer to its first element.
The difference between char exemplo[10] and char *exemplo[10] is that the first one declares an array of 10 characters and the second declares an array of 10 pointers.
08.10.2015 / 10:31
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You are not declaring a pointer to array . You are declaring a pointer to char . They are different things .
In the first example, you have an array with 10 char s. In the second it has an array with 10 pointer to char .
The pointer to char is almost synonymous with string . The C language does not have string , but this is closest to one.
Obviously the pointer needs to point to an area of memory that has a sequence of char s.
08.10.2015 / 03:32