I'm studying a book I found on the net, she asks for an exercise, but she did not teach how to do it in the previous pages, I tried and it did not work, thank you for your help.
Make a program that reads and stores any two integers in variables. Calculate and present the rest of the division of each other
float num1, num2, media;
printf("\n digite um valor: ");
scanf("%f",&num1);
printf("\n digite outro valor: ");
scanf("%f",&num2);
media = num1 % num2;
printf("\n %f \n", media);
In math it is only possible to find the rest when thinking of integers, so the type can not be float .
#include <stdio.h>
int main(void) {
int num1, num2, resto;
printf("\n digite um valor: ");
scanf("%d",&num1);
printf("\n digite outro valor: ");
scanf("%d",&num2);
resto = num1 % num2;
printf("\n %d \n", resto);
return 0;
}
See working on ideone .
Use meaningful variable names. If you are calculating the rest, call it resto and not media .
The reason your code does not work has already been addressed, use variables of type int so that the division returns the rest, not a number with decimals. Another interesting way to solve this remainder problem of division is by using only math. This is the process we naturally do in a split account with remainder, we multiply the resultado by the divisor ( num1 ) and subtract it from the dividend ( num2 ), so we have resto :
#include <stdio.h>
int main(void) {
int num1, num2, resultado, resto;
printf("\n digite um valor: ");
scanf("%d",&num1);
printf("\n digite outro valor: ");
scanf("%d",&num2);
resultado = num1 / num2;
resto = num1 - (resultado * num2);
printf("\n %d \n", resto);
return 0;
}
#include <stdio.h>
main() {
int a,b;
printf("Digite o valor do dividendo: ");
scanf("%d",&a);
printf("Digite o valor do divisor: ");
scanf("%d",&b);
while(a>=b)
a=a-b;
printf("\nResto: %d",a);
getchar();
}
In this method, the user types the first value (dividend) and then types the second value (divisor). The two values enter into a while loop whose main function is for the value of the first value (dividend) to exit the loop when the dividend is smaller than the dividend.
Example:
If the user types 35 for the dividend and 4 for the divisor, we have:
#include <stdio.h>
main() {
int a,b;
printf("Digite o valor do dividendo: ");
scanf("%d",&a);
printf("Digite o valor do divisor: ");
scanf("%d",&b);
while(a>=b) {
a=a-b;
printf("\nValor do dividendo por enquanto = %d",a); //Linha acrescentada para mostar o laço
}
printf("\nResto: %d",a);
getchar();
}
