def fnum_aleatorio(a, b, m, semente=None):
if semente != None:
num=semente
num_aleatorio = (num*a+b)%m
if num_aleatorio <= a//2:
return 0
else:
return 1
I'm trying to do a function that has a final result of 0 or 1, depending on the random number that was created, but I can not finish because of that error. how to proceed?
The problem is the scope of the num variable.
It is declared inside the if statement:
if semente != None:
num=semente
And you're trying to access it in the scope of the function:
num_aleatorio = (num*a+b)%m
It will give error because for the scope of the function fnum_aleatorio the variable num does not exist. It only exists within the scope of if .
One way to fix this is to do:
num = semente if semente is not None else 1 .
Where 1 is the default value of num when semente is None .
In this way you will be declaring the variable num within the scope of the function fnum_aleatorio .
So, I would stay:
def fnum_aleatorio(a, b, m, semente=None):
num = semente if semente is not None else 1
num_aleatorio = (num*a+b)%m
if num_aleatorio <= a//2:
return 0
else:
return 1
In your code you only start the variable num if the semente is different from None , if semente is equal a None the variable num will never be started, so there is no value in the variable to be used in the calculation in num_aleatorio = (num*a+b)%m , to solve this problem start the variable num with 0 (or any other value) outside the if (above preferably), see:
def fnum_aleatorio(a, b, m, semente=None):
num = 0
if semente != None:
num=semente
num_aleatorio = (num*a+b)%m
if num_aleatorio <= a//2:
return 0
else:
return 1