We have a VM in the azure.
I generated the homologation build and put it on the server.
Generated the files and index.html so
<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>DESIF</title>
<base href="/">
<link href="https://fonts.googleapis.com/icon?family=Material+Icons" rel="stylesheet">
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="icon" type="image/x-icon" href="favicon.ico">
</head>
<body>
<app-root>Carregando ...</app-root>
<script type="text/javascript" src="inline.bundle.js"></script><script type="text/javascript" src="polyfills.bundle.js"></script><script type="text/javascript" src="styles.bundle.js"></script><script type="text/javascript" src="vendor.bundle.js"></script><script type="text/javascript" src="main.bundle.js"></script></body>
</html>
On the Tomcat server. in the Program Files \ Apache Software Foundation \ Tomcat 8.5 \ webapps folder, I created the dist folder.
When you enter the address: link , it goes to the correct page, loading changes the address to link , which is correct, but I thought it would be: link
If you press F5 or CTRL + F5 , it goes to TOMCAT start.
Do I have to configure something?
No Angular, I have a file that has the Server address, in case it is ** link *, so you do not have to keep changing every time you go up for approval, do you have the angle to do this automatically, for some variable?
First time I deploy.
Is there any better way?
