Hello, can anyone help me with the following question?
Example I have an aob that represents an item (cigarette) in a game ...
XX XX XX XX XX XX XX XX = cigarette
Xx XX XX XX XX XX XX XX 01 = 1 cigar
XX XX XX XX XX XX XX XX 0A = 10 cigarettes
How to make the value of the item negative?
XX XX XX XX XX XX XX XX ?? = -10 cigarettes
If anyone can help me with this, I appreciate it.
Thank you
Try to do with Complement of 2 in Binary .
Transform the value you want to convert to binary: 0A = 1010
Now do the inversion ( NOT ) of the torque, that is, where is 0 will be and 1 and a where 1 will be 0:
1010 = 0101
Add +1 to the result: 0101 + 0001 = 0110 and it will have its negative number in binary: 0110 .
0110 in normal binary is 6 ). To solve this problem, you have to use the rest of the bits, for example:
The number 10 in 8 bits is: 0000 1010 , when doing the inversion it will be 1111 0101 , sum +1 and it will be 1111 0110 , ready, this and the -10 "identified" in binary (the number 6 is 0000 0110 ). However does not work for all variable types.
For example: In the case of a int signed that "reserves a space" for the identification of negative numbers, this operation would function normally. But with an int unsigned (where you do not have the "buffer" for a negative number), this would not work and the result would be 246 .
Now with your value, come on:
Transform to binary:
0000 0000 0000 000A = 0000 0000 0000 1010
Do the inversion:
0000 0000 0000 1010 = 1111 1111 1111 0101
Sum +1:
1111 1111 1111 0101 + 0001 = 1111 1111 1111 0110
Now with the binary negative number in hand, simply transforms to Hexadecimal: FFFF FFFF FFFF FFF6 .
The result of -10 is FFFF FFFF FFFF FFF6 . Try to use this value in your AoB.