Well, I'm having a hard time putting this together using for, I know how to make a program that displays even or odd numbers up to the number entered, but how do I display how many numbers the user reports in num ?
#include <stdio.h>
int main() {
int op, num, x;
printf("1.pares\n2.Impares\n");
scanf("%d", &op);
printf("Digite o numero de vezes que voce quer imprimir\n");
scanf("%d", &num);
if (op==1) { for (x=2; num>=x; x=x+2) {
printf("%d\n", x); }
}else if (op==2) {
for (x=1; num>=x; x=x+2) {
printf("%d\n", x);
}
}
}
The idea is for the user to choose between even or odd, and then choose how many numbers to display (eg, display 5 even numbers, display 3 odd numbers)