Calling HTML snippet in JavaScript

I'm using Django FrameWork for an application that searches videos on youtube. But there is an excerpt from JS, which calls an html where you "embed" the searched video. And I'm not sure how to create this route in Django.

JS looking for the video

function tplawesome(e,t){res=e;for(var n=0;n<t.length;n++){res=res.replace(/\{\{(.*?)\}\}/g,function(e,r){return t[n][r]})}return res}

$(function() {
    $("form").on("submit", function(e) {
       e.preventDefault();
       // prepare the request
       var request = gapi.client.youtube.search.list({
            part: "snippet",
            type: "video",
            q: encodeURIComponent($("#search").val()).replace(/%20/g, "+"),
            maxResults: 3,
            order: "viewCount",
            publishedAfter: "2015-01-01T00:00:00Z"
       });
       // execute the request
       request.execute(function(response) {
          var results = response.result;
          $("#results").html("");
          $.each(results.items, function(index, item) {
            $.get("busca/item.html", function(data) {
                $("#results").append(tplawesome(data, [{"title":item.snippet.title, "videoid":item.id.videoId}]));
            });
          });
          resetVideoHeight();
       });
    });

    $(window).on("resize", resetVideoHeight);
});

HTML that JS FLAME

<div class="item">
    <h2>{{title}}</h2>
    <iframe class="video w100" width="640" height="360" src="//www.youtube.com/embed/{{videoid}}" frameborder="0" allowfullscreen></iframe>
</div>

Views.py file where I create the route for the HTML file to be rendered

def busca(request):
    return render(request, 'busca/item.html')

When I search, you are giving 404 in the search / item.html