Optimizing data output

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Optimizing data output

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Good morning:

I made this code for an exercise. My question is: How can I optimize the outputs without having to make multiple prints. In that code I made for three outputs. Only if it was for 10 outputs I would have to make 10 prints. Another question I have. In the text "the value of the commission of the FIRST representative ..." ... this term ... first ... second ... third ... is there any way I can leave it automated without having to type one by one . Below is my code.

itens = []
item=0
valor_item = 50

for i in range(3):
    item = int(input("\nQuantidade de itens do %dº representante: " % (i+1)))
    itens.append(item)


comissoes = []
for item in itens:
    comissao = (0.1*valor_item*item) if item <= 19 else \
               (0.15*valor_item*item) if item >=20 and item<= 49 else \
               (0.20*valor_item*item) if item >=50 and item <=74 else \
               (0.25*valor_item*item) 
    comissoes.append(comissao)


print("\nValor da Comissão do do Primeiro Representante: R$ %5.2f% " %comissoes[0])
print("\nValor da Comissão do do Segundo Representante: R$ %5.2f% " %comissoes[1])
print("\nValor da Comissão do do Terceiro Representante: R$ %5.2f% " %comissoes[2])

Thank you for your attention

python-3.x

asked by anonymous 01.11.2018 / 13:29

1 answer

Does not reach notification How to solve: Column "id" not found [42122-197]?

score 0 · Answer 1

Use a for loop, just as you did to set the comissoes list.

for indice, comissao in enumerate(comissoes, start=1):
    print("\nValor da Comissão do %dº Representante: R$ %5.2f" % (indice, comissao))

Docs for function enumerate : link

As for your code as a whole, you can do everything with a single loop and without using lists.

quantidade_representantes = 3
valor_item = 50

for i in range(1, quantidade_representantes + 1):
    item = int(input("\nQuantidade de itens do %dº representante: " % i))

    if item <= 19:
        multiplicador_comissao = 0.10
    elif item <= 49:
        multiplicador_comissao = 0.15
    elif item <= 74:
        multiplicador_comissao = 0.20
    else:
        multiplicador_comissao = 0.25

    comissao = multiplicador_comissao * valor_item * item

    print("Comissão do %dº representante: R$ %5.2f" % (i, comissao))
    print()

It's just a tip.