Return of data in form inputs

Question

Return of data in form inputs

Navigation

#1 by (0 votes)

0

Hello! I have some clients registered in the database, the customer choice is made through a select select that returns me the data in another select form. I would like to return the data in form different and separate input type. Type address in one input, neighborhood in another, and so on. Could someone direct me how do I?

<?php
    require_once ("DBController.php");
    $db_handle = new DBController();
    $query = "SELECT * FROM clientes";
    $clienteResult = $db_handle->runQuery($query);
    ?>
    <html>
    <head>
    <TITLE>Retornar dados nos input</TITLE>


    <head>
    <style>
    body {
        width: 610px;
        font-family: calibri;
    }

    .form-DronpDown {
        border: 1px solid #7ddaff;
        background-color: #C8EEFD;
        margin: 2px 0px;
        padding: 40px;
        border-radius: 4px;
    }

    .form-control {
        padding: 10px;
        border: #bdbdbd 1px solid;
        border-radius: 4px;
        background-color: #FFF;
        width: 50%;
    }

    .row {
        padding-bottom: 15px;
    }
    </style>
    <script src="https://code.jquery.com/jquery-3.3.1.min.js"type="text/javascript"></script>
    <script>
    function getdados() {
            var str='';
            var val=document.getElementById('cliente-list');
            for (i=0;i< val.length;i++) { 
                if(val[i].selected){
                    str += val[i].value + ','; 
                }
            }         
            var str=str.slice(0,str.length -1);

        $.ajax({          
                type: "GET",
                url: "get_dados.php",
                data:'clienteID='+str,
                success: function(data){
                    $("#dados-list").html(data);
                }
        });
    }
    </script>
    </head>
    <body>
        <div class="form-DronpDown">
    <div class="row">

    <label>cliente:</label><br /> 
    <select name="cliente[]"  id="cliente-list" class="form-control" onChange="getdados();" >
    <option value="">Select cliente</option>

    <?php
    foreach ($clienteResult as $cliente) {
        ?>
    <option value="<?php echo $cliente["id"]; ?>"><?php echo $cliente["cliente_name"]; ?></option>
    <?php
    }
    ?>

    </select>
    </div>

            <div class="row">
                <label>Dados:</label><br /> 
                <div name="dados[]"  id="dados-list" class="form-control"  size=5></div>
            </div>
        </div>
    </body>
    </html>

php

asked by anonymous 03.11.2018 / 23:18

1 answer

Error deserializing a Json List in Java How to use socket with JSON-RPC?

score 0 · Answer 1

If the data you say is in the javascript function, you can play the data anywhere.

For example:

...
success: function(data){
     document.querySelector('#endereco').value = data.endereco
     document.querySelector('#cidade').value = data.cidade
}

And in html contain the inputs

<input id="endereco">
<input id="cidade">