This seems to be the same problem covered in How to assign elements of a list to different variables in Python? .
When you study all the mechanisms of the language before you start to create programs that are more useful than isolated exercise I discovered that Python has a mechanism called list. It is a vector ( array ) up to a little more flexible. This type of data structure serves to put several values under the same variable, so you do not have to create a myriad of them, you do not need to know how many you need (in some languages the basic array of initializing it, Pyhton already has a mechanism that allows it to grow if necessary).
When you use an array or a list, which looks like an array that you must have learned in school, you access each element by an index, that number you are using in variable names , but it stays isolated and can be used up to a variable inside it, which gives a lot of flexibility.
I'll use the name you used, but it would be better to use more meaningful names:
objeto.a[1]
objeto.a[2]
.
.
.
objeto.a[N]
An approximate code you need to add to the loop that reads the file would be:
lista.append(Obj())
Being Obj would be this class that created an object by reading a file data.
