How to display the name of the image that is in the bank in the view with Laravel?

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How to display the name of the image that is in the bank in the view with Laravel?

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#1 by (0 votes)

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Good evening.

I'm having trouble performing an update on an image with Laravel on the Mysql database.

The store method of my controller looks like this:

public function store(Request $request){
    $filename = $request->imagem->getClientOriginalName();
    $banners = new Banner;
    $banners->titulo = $request->titulo;
    $banners->descricao = $request->descricao;
    $banners->imagem = $request->file('imagem')->storeAs('banners/', $filename);
    $banners->save();
    return redirect()->route('banner.index')->with('message', 'Banner publicado com sucesso!');

}

And update method, it looks like this:

public function update(Request $request, $id) {
    $banners = Banner::findOrFail($id);
    $banners->titulo = $request->titulo;
    $banners->descricao = $request->descricao;
    $banners->imagem = $request->file('imagem')->storeAs('banners');
    $banners->save();
    return redirect()->route('banner.index')->with('message', 'Banner alterado com sucesso!');

}

My view Change this way:

<div class="row">
    <div class="col-12">
        <form method="post" action="{{ route('banner.update', $banner->id) }}" enctype="multipart/form-data">
        {{ method_field('PATCH') }}
        {{ csrf_field() }}

        <div class="card">
            <div class="card-body">
                <div class="row">
                    <div class="col-lg-12">
                        <div class="form-row">
                            <div class="form-group col-lg-9">
                                <label for="simpleinput">Título</label>
                                <input type="text" id="simpleinput" value="{{ $banner->titulo }}" class="form-control" name="titulo">
                            </div>
                        </div>

                        <div class="form-row">
                            <div class="form-group col-lg-9">
                                <label for="example-fileinput">Imagem</label><i class="mdi mdi-information"  data-toggle="tooltip" data-placement="top" title="" data-original-title="Tamanho recomendado 1920pxx800px"></i>
                                <input type="file" id="example-fileinput" value="{{ $banner->imagem }}" class="form-control-file" name="imagem" accept=".gif,.jpg,.png">
                            </div>
                        </div>

                        <div class="form-row">
                            <div class="form-group col-lg-9">
                                <label for="simpleinput">Descrição</label>
                                <textarea rows="4" id="example-textarea" class="form-control" name="descricao">{{ $banner->descricao }}</textarea>
                            </div>
                        </div>
                </div>
            </div>
        </div>
    </div>
    <button type="submit" class="btn btn-primary">Publicar</button>
    <a type="button" class="btn btn-link" href="{{route('banner.index')}}">Voltar</a>
</form>

In this way, the only thing you can do is replace one image with another.

I would like to know how I can display the name of the image that is in the database and maintain it, if no changes are made to the image, with changes only in the texts.

php laravel

asked by anonymous 12.12.2018 / 02:17

1 answer

Django 1.11 ManyToMany Ford-Fulkerson Python Algorithm

score 0 · Accepted Answer

You need to put a condition to check if any files have been uploaded. To do this, simply use the hasFile() method.

In your case it would look something like this:

public function update(Request $request, $id) {
    $banners = Banner::findOrFail($id);
    $banners->titulo = $request->titulo;
    $banners->descricao = $request->descricao;
    if ($request->hasFile('imagem')) {    
        $banners->imagem = $request->file('imagem')->storeAs('banners');
    }
    $banners->save();
    return redirect()->route('banner.index')->with('message', 'Banner alterado com sucesso!');
}

On the blades, just create a condition:

@if($banner->imagem) 
<!-- Aqui dentro HTML, recomendo colocar uma img acerte o Css (adeque o src ao caminho publico da sua imagem) -->    
<img src="{{$banner->imagem}}" />
@endif