SIGSEGV error in using a pointer

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SIGSEGV error in using a pointer

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#1 by (1 votes)

0

I have the following problem: I'm creating a pointer and allocating memory in it, passing its reference to function, but when I read it in function the error occurs in the title.

Function:

void FileLer(char *texto, char *file)
{
    //
    //  Retorno
    //
    int ret = 99;

    //
    //  Handle
    //
    UINT FileHandleLer = 0;

    //
    //  Tamanho do Buffer
    //
    UINT BufferLenLer = 0;

    //
    //  Pega o tamanho do arquivo
    //
    GEDI_FS_FileSizeGet(file, 1, &BufferLenLer);

    if(BufferLenLer > 0)
    {

        GEDI_LCD_DrawString(5,  FONT_HEIGHT*5, FONT_WIDTH*0.7, FONT_HEIGHT*0.7, "File Ok! %d", BufferLenLer);

        GEDI_CLOCK_Delay(1000);

    }
    else
    {

        GEDI_LCD_DrawString(5, FONT_HEIGHT*5, FONT_WIDTH*0.7, FONT_HEIGHT*0.7, "Erro! ");

        GEDI_CLOCK_Delay(1000);

        //
        //  Para a funcao
        //
        return;

    }

    //
    //  Abre um arquivo
    //
    ret = GEDI_FS_FileOpen(file, 3, GEDI_FS_STORAGE_PUBLIC, &FileHandleLer);

    ret = GEDI_FS_FileRead(FileHandleLer, &texto, &BufferLenLer);

    int b = strlen(texto);     <<<<<< -- Linha com o erro 

    //
    //  Fecha o socket
    //
    ret = GEDI_FS_FileClose(FileHandleLer);

    //
    //  Zera Variaveis
    //
    ret                 =   0;
    FileHandleLer       =   0;
    BufferLenLer        =   0;
}

Call:

char *buffer            =   (char *)malloc(1024*(sizeof(char)));

//
//  Le o arquivo IP
//
FileLer(buffer, "configIP.txt");

c ponteiro posix

asked by anonymous 22.08.2016 / 15:48

1 answer

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score 1 · Accepted Answer

void FileLer(char *texto, char *file)
{
    // ...
    ret = GEDI_FS_FileRead(FileHandleLer, &texto, &BufferLenLer);
    //                                    ^^^^^^
    // ...
}

&texto and texto are different things. The first has type char ** , the second has type char * . The first points to a local variable to the function FileLer() , the second points to an external string.