I have a file that has the format nome1-nome2-0.0.0.0.war , and through the shell I wanted to get the version (0.0.0.0) and save it in a variable and then use it to create a directory .
Note: Versions change, but the names and extension are the same. Thank you!
You can do it in some ways, one of them is:
ls nome1-nome2-0.0.0.0.war| egrep -wo '[\.0-9]+'
The output of this will be: 0.0.0.0
Explanation:
I created a file named name1-name2-0.0.0.0.war , I executed agrep using the following regex '[\.0-9]+' , the parameter o and w , it was necessary to match only what the regex contemplated.
A script that will scan a folder and create other folders based on the versions of your app, could be:
#!/bin/bash
for i in $(ls *.war|egrep -wo '[\.0-9]+')
do
mkdir $i
done
ls *.war | awk -F '-' {'print $3'} | awk -F '.war' {'print $1'}
while read versao
do
mkdir $versao
done