I'm wondering if there are any repeated values in the array.
Here is the code I tried, but I did not succeed.
#include <stdio.h>
int main(int argc, char** argv)
{
int a, i, j, c = 0;
scanf("%d", &a);
int vetor[a];
for(i = 0; i < a; i++)
{
scanf("%d", &vetor[i]);
}
for(i = 0; i < a; i++)
{
for(j = 0; j < a; j++)
{
if(vetor[i] == vetor[j])
{
c++;
}
}
}
printf("%d\n",c);
return 0;
}
As you put it, there will be a cases where i and j are equal and therefore vetor[i] and vetor[j] are equal, after all comparing a vector position with itself will always result in equal elements being compared. This case is not interesting and should not be counted.
Another thing is that counting i and j , both from 0 to a - 1 , if in position 3 and in position 5 there is a repetition, it will be counted twice, one with i = 3 and j = 5 and another with i = 5 and j = 3 .
So if there are x repetitions, your program is giving 2 * x + a .
The solution to both problems is simply to change the j = 0 of% internal for by j = i + 1 .
See the corrected code:
#include <stdio.h>
int main(int argc, char** argv) {
int a, i, j, c = 0;
scanf("%d", &a);
int vetor[a];
for (i = 0; i < a; i++) {
scanf("%d", &vetor[i]);
}
for (i = 0; i < a; i++) {
for (j = i + 1; j < a; j++) {
if (vetor[i] == vetor[j]) {
c++;
}
}
}
printf("%d\n", c);
return 0;
}