In scripts php, we can, when executed by the command line, capture its values of the arguments passed through the variable $argv and its number through the variable $argc .
For example (Script):
echo 'My name is ', $argv[1]
Example call:
my_name_is.php Wallace
The output will be:
My name is Wallace
And not Python ? Is there any way to capture the arguments passed to a script via the command line?
According to this response from SOen , you can import the sys library, some examples:
import sys
print "\n".join(sys.argv)
Another example with sys
import sys
for value in sys.argv:
print value
Generally, the first argument of argv is always the name of the script that is running.
For example:
> args.py one two tree
Return
['args.py', 'one', 'two', 'tree']
If you want to return from the argument 1 on (lists start counting 0% with%), you can use zero to cut the first element of the argument list.
So:
print sys.argv[1:]
Return:
['one', 'two', 'tree']
If you still want to use the slice variable without having to invoke it from the argv module, you can do this:
from sys import argv
print argv[1:]
I know there are other ways to do, just as Python has different libraries for similar purposes, I'll edit and add more later, I think the example would look like this:
import sys
print 'Meu nome é ', sys.argv[1]