Good afternoon, could anyone help me with this problem? I have no idea what's going on ....
Next, I have a select that selects the city, and then the follow-up as selected in the city, so far, it works and everything, but I just put the class "selectpicker" bootstrap, stops working , do not load anymore, I would like to put this class to make it more presentable. Follow the code.
Filter:
<!-- quick search -->
<form id="quick-search" class="quick-search" method="post" action="<?php echo $urlOrigem?>/resultado/">
<fieldset>
<legend>Convênios:</legend>
<select name="cidades" id="cidade">
<option>Selecione Uma Cidade</option>
<?php
$sql = mysql_query("SELECT * FROM convenioscidades ORDER BY name ASC")or die(mysql_error());
while($dados = mysql_fetch_array($sql)){
?>
<option value="<?php echo $dados['name'];?>"><?php echo $dados['name'];?></option>
<?php }?>
</select>
<select name="cat" id="convenios">
<option value="0">Aguardando cidade...</option>
</select>
<button type="submit">Procurar</button>
<div class="switcher">
<button id="quick-search-switcher" type="button">Convênios</button>
</div>
</fieldset>
</form>
FILTER JS:
$(function(){
var url = location.href; //pega endereço que esta no navegador
url = url.split("/"); //quebra o endeço de acordo com a / (barra)
var teste = 'testedsds';
$("select[name=cidades]").change(function(){
beforeSend:$("select[name=cat]").html('<option value="0">Aguardando Carregando...</option>');
var cat = $("select[name=cidades]").val();
$.post ("http://localhost/dlcor_2017/convenios.php",{cat: cat}, function(pega_cat){
complete:$("select[name=cat]").html(pega_cat);
});
});
})
If anyone can help me, I'll be very grateful, Thanks!