Comparison between random number and typed number never says you got it right, even the numbers being equal

When you do

if n == (randint):  

You are comparing n with randint , which is a function and not the value drawn (note that functions are objects in Python). This comparison will always be negative in your case.

Save the value drawn in a variable so you can compare later. For example:

numero_sorteado = randint(1, 2)

And, at the time of the comparison, be aware of the types. the function input() returns a string, then convert it to a number with the function int before comparing:

n = int(input('Digite um número: '))  
numero_sorteado = randint(1, 2)
print(numero_sorteado)  
if n == numero_sorteado:  
    print ('Você ganhou!')  
else:  
    print ('Você perdeu!')  

I think this is what you want:

from random import randint
if int(input('Digite um número: ')) == randint( 1, 2):
    print ('Você ganhou!')
else:
    print ('Você perdeu!')

You did not convert from string to int into data entry and did not save the generated random number into a variable to test later. This code is still a bit flawed, but it works most of the time, for an hour I think it's good, after all it's learning in an unstructured way and it does not go that far.

Then, the way your code looks, the comparison made by 'if' is basically a string (text representation, in this case a number 1 or 2), with an integer (the number itself and not a string its representation):

if n == (randint)

Given that there is no variable storing the first randint , you are basically running a randint 'x' method (generating an 'x' ), showing this 'x' method for the user, and then executing a 'randint' 'y' method, and using that method for comparison with the user input.

So I suggest storing 'randint' into a variable of type int (integer), show this variable store to the user and use it in the comparison.

Just complementing the other answers. You can also use a ternary operator to complete this routine of verifying the number with the number raffled and simplify the code a little more, see below:

from random import randint

print("Você ganhou!") if int(input("Numero: ")) == randint(1, 2) else print("Você perdeu!")

The syntax of this operator is as follows

x if condicao else y

If the condition int(input("Numero: ")) == randint(1, 2) is true, the statement on the left side of if is executed, otherwise the statement to be executed will be of the else command.

See working at repl.it .