There is another way than with% E in c, why did I do this and uri gave 10% error. Issue Link
My code.
#include <stdio.h>
int main(int argc, char** argv)
{
double teste;
scanf("%lf", &teste);
if(teste == -0)
{
printf("+0.0000E+00\n");
}
else
{
printf("%+.4E\n", teste);
}
return 0;
}
The problem is that you print the value "+ 0.0000E + 00 \ n" for -0 entries.
Due to the limitation of the range of values that double can take in cases of very small negative numbers the value can be truncated to -0.0000E + 00, so your if makes it "+ 0.0000E + 00" which it is not a valid output.
Take a look at the IEEE 754 standard for the range question and on that other link the +0 and -0 .